20x^2=8x

Solution for 20x^2=8x equation:

20x^2=8x

We move all terms to the left:

20x^2-(8x)=0

a = 20; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·20·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*20}=\frac{0}{40}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*20}=\frac{16}{40}
=2/5
$